For example choose the number 3:
Add up the cubes of all the numbers from 1 to 3:
13 + 23 + 33 = 1 + 8 + 27 = 36
Now, add up all the numbers from 1 to your number
1 + 2 + 3 = 6
and then square the result
62 = 36
The answers are the same.
In algebraic notation:
13 + 23 + 33 + ... + n3 = (1 + 2 + 3 + ... + n)2
We can show this with pictures:
It obviously works for 1:
13 = 12
* = *
for 2:
(1 + 2)2 =
* * * * * * * * *remove one to the side. This is the 13. We need to show that the rest is 23.
* * * * * * * * *The remaining has a 22 in it. Separate that out
* * * * * * * * *Move the two at the top to match the two at the side:
* * * * * * * * *Two lots of 22 makes 23.
= 13 + 23
Now the case for 3:
(1 + 2 + 3)2 =
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *move 32 to one side. We already know that this is 13 + 23. So we need to show that the rest is 33.
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *The remaining has a 32 in it at the bottom left. Separate that out
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *We have 3 lots of 32 which is 33.
= 13 + 23 + 33
We actually got a bit lucky with this one. The next case shows what we need to do for any size.
(1 + 2 + 3 + 4)2 =
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *move 62 to one side. We already know that this is 13 + 23 + 33. So we need to show that the rest is 43.
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *The remaining has a 42 in it at the bottom left. Separate that out
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *The parts above and beside the 42 have side length 1+2+3. Separate it out this way.
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *Move those above the square to be with those beside the square. Matching the longest with the shortest and so on, 3 next to 1, 2 next to 2 and 1 next to 3.
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *Bunch together to make 4 squares
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *We now have 4 lots of 42 which is 43
= 13 + 23 + 33 + 43
This procedure can be applied to the general case n.
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